Integrand size = 33, antiderivative size = 250 \[ \int \cos ^5(c+d x) (a+b \sec (c+d x))^4 \left (A+C \sec ^2(c+d x)\right ) \, dx=\frac {1}{2} a b \left (4 b^2 (A+2 C)+a^2 (3 A+4 C)\right ) x+\frac {b^4 C \text {arctanh}(\sin (c+d x))}{d}+\frac {\left (6 A b^4+2 a^4 (4 A+5 C)+a^2 b^2 (56 A+85 C)\right ) \sin (c+d x)}{15 d}+\frac {a b \left (6 A b^2+a^2 (29 A+40 C)\right ) \cos (c+d x) \sin (c+d x)}{30 d}+\frac {\left (3 A b^2+a^2 (4 A+5 C)\right ) \cos ^2(c+d x) (a+b \sec (c+d x))^2 \sin (c+d x)}{15 d}+\frac {A b \cos ^3(c+d x) (a+b \sec (c+d x))^3 \sin (c+d x)}{5 d}+\frac {A \cos ^4(c+d x) (a+b \sec (c+d x))^4 \sin (c+d x)}{5 d} \]
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Time = 0.96 (sec) , antiderivative size = 250, normalized size of antiderivative = 1.00, number of steps used = 8, number of rules used = 7, \(\frac {\text {number of rules}}{\text {integrand size}}\) = 0.212, Rules used = {4180, 4179, 4159, 4132, 8, 4130, 3855} \[ \int \cos ^5(c+d x) (a+b \sec (c+d x))^4 \left (A+C \sec ^2(c+d x)\right ) \, dx=\frac {a b \left (a^2 (29 A+40 C)+6 A b^2\right ) \sin (c+d x) \cos (c+d x)}{30 d}+\frac {\left (a^2 (4 A+5 C)+3 A b^2\right ) \sin (c+d x) \cos ^2(c+d x) (a+b \sec (c+d x))^2}{15 d}+\frac {1}{2} a b x \left (a^2 (3 A+4 C)+4 b^2 (A+2 C)\right )+\frac {\left (2 a^4 (4 A+5 C)+a^2 b^2 (56 A+85 C)+6 A b^4\right ) \sin (c+d x)}{15 d}+\frac {A \sin (c+d x) \cos ^4(c+d x) (a+b \sec (c+d x))^4}{5 d}+\frac {A b \sin (c+d x) \cos ^3(c+d x) (a+b \sec (c+d x))^3}{5 d}+\frac {b^4 C \text {arctanh}(\sin (c+d x))}{d} \]
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Rule 8
Rule 3855
Rule 4130
Rule 4132
Rule 4159
Rule 4179
Rule 4180
Rubi steps \begin{align*} \text {integral}& = \frac {A \cos ^4(c+d x) (a+b \sec (c+d x))^4 \sin (c+d x)}{5 d}+\frac {1}{5} \int \cos ^4(c+d x) (a+b \sec (c+d x))^3 \left (4 A b+a (4 A+5 C) \sec (c+d x)+5 b C \sec ^2(c+d x)\right ) \, dx \\ & = \frac {A b \cos ^3(c+d x) (a+b \sec (c+d x))^3 \sin (c+d x)}{5 d}+\frac {A \cos ^4(c+d x) (a+b \sec (c+d x))^4 \sin (c+d x)}{5 d}+\frac {1}{20} \int \cos ^3(c+d x) (a+b \sec (c+d x))^2 \left (4 \left (3 A b^2+a^2 (4 A+5 C)\right )+4 a b (7 A+10 C) \sec (c+d x)+20 b^2 C \sec ^2(c+d x)\right ) \, dx \\ & = \frac {\left (3 A b^2+a^2 (4 A+5 C)\right ) \cos ^2(c+d x) (a+b \sec (c+d x))^2 \sin (c+d x)}{15 d}+\frac {A b \cos ^3(c+d x) (a+b \sec (c+d x))^3 \sin (c+d x)}{5 d}+\frac {A \cos ^4(c+d x) (a+b \sec (c+d x))^4 \sin (c+d x)}{5 d}+\frac {1}{60} \int \cos ^2(c+d x) (a+b \sec (c+d x)) \left (4 b \left (6 A b^2+a^2 (29 A+40 C)\right )+4 a \left (9 b^2 (3 A+5 C)+2 a^2 (4 A+5 C)\right ) \sec (c+d x)+60 b^3 C \sec ^2(c+d x)\right ) \, dx \\ & = \frac {a b \left (6 A b^2+a^2 (29 A+40 C)\right ) \cos (c+d x) \sin (c+d x)}{30 d}+\frac {\left (3 A b^2+a^2 (4 A+5 C)\right ) \cos ^2(c+d x) (a+b \sec (c+d x))^2 \sin (c+d x)}{15 d}+\frac {A b \cos ^3(c+d x) (a+b \sec (c+d x))^3 \sin (c+d x)}{5 d}+\frac {A \cos ^4(c+d x) (a+b \sec (c+d x))^4 \sin (c+d x)}{5 d}-\frac {1}{120} \int \cos (c+d x) \left (-8 \left (6 A b^4+2 a^4 (4 A+5 C)+a^2 b^2 (56 A+85 C)\right )-60 a b \left (4 b^2 (A+2 C)+a^2 (3 A+4 C)\right ) \sec (c+d x)-120 b^4 C \sec ^2(c+d x)\right ) \, dx \\ & = \frac {a b \left (6 A b^2+a^2 (29 A+40 C)\right ) \cos (c+d x) \sin (c+d x)}{30 d}+\frac {\left (3 A b^2+a^2 (4 A+5 C)\right ) \cos ^2(c+d x) (a+b \sec (c+d x))^2 \sin (c+d x)}{15 d}+\frac {A b \cos ^3(c+d x) (a+b \sec (c+d x))^3 \sin (c+d x)}{5 d}+\frac {A \cos ^4(c+d x) (a+b \sec (c+d x))^4 \sin (c+d x)}{5 d}-\frac {1}{120} \int \cos (c+d x) \left (-8 \left (6 A b^4+2 a^4 (4 A+5 C)+a^2 b^2 (56 A+85 C)\right )-120 b^4 C \sec ^2(c+d x)\right ) \, dx+\frac {1}{2} \left (a b \left (4 b^2 (A+2 C)+a^2 (3 A+4 C)\right )\right ) \int 1 \, dx \\ & = \frac {1}{2} a b \left (4 b^2 (A+2 C)+a^2 (3 A+4 C)\right ) x+\frac {\left (6 A b^4+2 a^4 (4 A+5 C)+a^2 b^2 (56 A+85 C)\right ) \sin (c+d x)}{15 d}+\frac {a b \left (6 A b^2+a^2 (29 A+40 C)\right ) \cos (c+d x) \sin (c+d x)}{30 d}+\frac {\left (3 A b^2+a^2 (4 A+5 C)\right ) \cos ^2(c+d x) (a+b \sec (c+d x))^2 \sin (c+d x)}{15 d}+\frac {A b \cos ^3(c+d x) (a+b \sec (c+d x))^3 \sin (c+d x)}{5 d}+\frac {A \cos ^4(c+d x) (a+b \sec (c+d x))^4 \sin (c+d x)}{5 d}+\left (b^4 C\right ) \int \sec (c+d x) \, dx \\ & = \frac {1}{2} a b \left (4 b^2 (A+2 C)+a^2 (3 A+4 C)\right ) x+\frac {b^4 C \text {arctanh}(\sin (c+d x))}{d}+\frac {\left (6 A b^4+2 a^4 (4 A+5 C)+a^2 b^2 (56 A+85 C)\right ) \sin (c+d x)}{15 d}+\frac {a b \left (6 A b^2+a^2 (29 A+40 C)\right ) \cos (c+d x) \sin (c+d x)}{30 d}+\frac {\left (3 A b^2+a^2 (4 A+5 C)\right ) \cos ^2(c+d x) (a+b \sec (c+d x))^2 \sin (c+d x)}{15 d}+\frac {A b \cos ^3(c+d x) (a+b \sec (c+d x))^3 \sin (c+d x)}{5 d}+\frac {A \cos ^4(c+d x) (a+b \sec (c+d x))^4 \sin (c+d x)}{5 d} \\ \end{align*}
Time = 2.52 (sec) , antiderivative size = 223, normalized size of antiderivative = 0.89 \[ \int \cos ^5(c+d x) (a+b \sec (c+d x))^4 \left (A+C \sec ^2(c+d x)\right ) \, dx=\frac {120 a b \left (4 b^2 (A+2 C)+a^2 (3 A+4 C)\right ) (c+d x)-240 b^4 C \log \left (\cos \left (\frac {1}{2} (c+d x)\right )-\sin \left (\frac {1}{2} (c+d x)\right )\right )+240 b^4 C \log \left (\cos \left (\frac {1}{2} (c+d x)\right )+\sin \left (\frac {1}{2} (c+d x)\right )\right )+30 \left (8 A b^4+12 a^2 b^2 (3 A+4 C)+a^4 (5 A+6 C)\right ) \sin (c+d x)+240 a b \left (A b^2+a^2 (A+C)\right ) \sin (2 (c+d x))+5 a^2 \left (24 A b^2+a^2 (5 A+4 C)\right ) \sin (3 (c+d x))+30 a^3 A b \sin (4 (c+d x))+3 a^4 A \sin (5 (c+d x))}{240 d} \]
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Time = 0.84 (sec) , antiderivative size = 195, normalized size of antiderivative = 0.78
method | result | size |
parallelrisch | \(\frac {-240 C \ln \left (\tan \left (\frac {d x}{2}+\frac {c}{2}\right )-1\right ) b^{4}+240 C \ln \left (\tan \left (\frac {d x}{2}+\frac {c}{2}\right )+1\right ) b^{4}+240 a b \left (\left (A +C \right ) a^{2}+A \,b^{2}\right ) \sin \left (2 d x +2 c \right )+\left (\left (25 A +20 C \right ) a^{4}+120 A \,a^{2} b^{2}\right ) \sin \left (3 d x +3 c \right )+30 A \,a^{3} b \sin \left (4 d x +4 c \right )+3 a^{4} A \sin \left (5 d x +5 c \right )+\left (\left (150 A +180 C \right ) a^{4}+1080 b^{2} \left (A +\frac {4 C}{3}\right ) a^{2}+240 A \,b^{4}\right ) \sin \left (d x +c \right )+360 a x b d \left (\left (A +\frac {4 C}{3}\right ) a^{2}+\frac {4 b^{2} \left (A +2 C \right )}{3}\right )}{240 d}\) | \(195\) |
derivativedivides | \(\frac {\frac {a^{4} A \left (\frac {8}{3}+\cos \left (d x +c \right )^{4}+\frac {4 \cos \left (d x +c \right )^{2}}{3}\right ) \sin \left (d x +c \right )}{5}+\frac {a^{4} C \left (2+\cos \left (d x +c \right )^{2}\right ) \sin \left (d x +c \right )}{3}+4 A \,a^{3} b \left (\frac {\left (\cos \left (d x +c \right )^{3}+\frac {3 \cos \left (d x +c \right )}{2}\right ) \sin \left (d x +c \right )}{4}+\frac {3 d x}{8}+\frac {3 c}{8}\right )+4 a^{3} b C \left (\frac {\sin \left (d x +c \right ) \cos \left (d x +c \right )}{2}+\frac {d x}{2}+\frac {c}{2}\right )+2 A \,a^{2} b^{2} \left (2+\cos \left (d x +c \right )^{2}\right ) \sin \left (d x +c \right )+6 C \,a^{2} b^{2} \sin \left (d x +c \right )+4 a A \,b^{3} \left (\frac {\sin \left (d x +c \right ) \cos \left (d x +c \right )}{2}+\frac {d x}{2}+\frac {c}{2}\right )+4 C a \,b^{3} \left (d x +c \right )+A \,b^{4} \sin \left (d x +c \right )+C \,b^{4} \ln \left (\sec \left (d x +c \right )+\tan \left (d x +c \right )\right )}{d}\) | \(240\) |
default | \(\frac {\frac {a^{4} A \left (\frac {8}{3}+\cos \left (d x +c \right )^{4}+\frac {4 \cos \left (d x +c \right )^{2}}{3}\right ) \sin \left (d x +c \right )}{5}+\frac {a^{4} C \left (2+\cos \left (d x +c \right )^{2}\right ) \sin \left (d x +c \right )}{3}+4 A \,a^{3} b \left (\frac {\left (\cos \left (d x +c \right )^{3}+\frac {3 \cos \left (d x +c \right )}{2}\right ) \sin \left (d x +c \right )}{4}+\frac {3 d x}{8}+\frac {3 c}{8}\right )+4 a^{3} b C \left (\frac {\sin \left (d x +c \right ) \cos \left (d x +c \right )}{2}+\frac {d x}{2}+\frac {c}{2}\right )+2 A \,a^{2} b^{2} \left (2+\cos \left (d x +c \right )^{2}\right ) \sin \left (d x +c \right )+6 C \,a^{2} b^{2} \sin \left (d x +c \right )+4 a A \,b^{3} \left (\frac {\sin \left (d x +c \right ) \cos \left (d x +c \right )}{2}+\frac {d x}{2}+\frac {c}{2}\right )+4 C a \,b^{3} \left (d x +c \right )+A \,b^{4} \sin \left (d x +c \right )+C \,b^{4} \ln \left (\sec \left (d x +c \right )+\tan \left (d x +c \right )\right )}{d}\) | \(240\) |
risch | \(\frac {3 a^{3} A b x}{2}+2 A a \,b^{3} x +2 C \,a^{3} b x +4 C a \,b^{3} x +\frac {5 i a^{4} A \,{\mathrm e}^{-i \left (d x +c \right )}}{16 d}-\frac {5 i a^{4} A \,{\mathrm e}^{i \left (d x +c \right )}}{16 d}+\frac {3 i {\mathrm e}^{-i \left (d x +c \right )} C \,a^{2} b^{2}}{d}-\frac {3 i {\mathrm e}^{i \left (d x +c \right )} a^{4} C}{8 d}-\frac {i {\mathrm e}^{i \left (d x +c \right )} A \,b^{4}}{2 d}+\frac {9 i {\mathrm e}^{-i \left (d x +c \right )} A \,a^{2} b^{2}}{4 d}-\frac {9 i {\mathrm e}^{i \left (d x +c \right )} A \,a^{2} b^{2}}{4 d}+\frac {3 i {\mathrm e}^{-i \left (d x +c \right )} a^{4} C}{8 d}+\frac {i {\mathrm e}^{-i \left (d x +c \right )} A \,b^{4}}{2 d}-\frac {3 i {\mathrm e}^{i \left (d x +c \right )} C \,a^{2} b^{2}}{d}+\frac {\ln \left ({\mathrm e}^{i \left (d x +c \right )}+i\right ) C \,b^{4}}{d}-\frac {\ln \left ({\mathrm e}^{i \left (d x +c \right )}-i\right ) C \,b^{4}}{d}+\frac {a^{4} A \sin \left (5 d x +5 c \right )}{80 d}+\frac {A \,a^{3} b \sin \left (4 d x +4 c \right )}{8 d}+\frac {5 a^{4} A \sin \left (3 d x +3 c \right )}{48 d}+\frac {\sin \left (3 d x +3 c \right ) A \,a^{2} b^{2}}{2 d}+\frac {\sin \left (3 d x +3 c \right ) a^{4} C}{12 d}+\frac {\sin \left (2 d x +2 c \right ) A \,a^{3} b}{d}+\frac {\sin \left (2 d x +2 c \right ) a A \,b^{3}}{d}+\frac {\sin \left (2 d x +2 c \right ) a^{3} b C}{d}\) | \(427\) |
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Time = 0.29 (sec) , antiderivative size = 195, normalized size of antiderivative = 0.78 \[ \int \cos ^5(c+d x) (a+b \sec (c+d x))^4 \left (A+C \sec ^2(c+d x)\right ) \, dx=\frac {15 \, C b^{4} \log \left (\sin \left (d x + c\right ) + 1\right ) - 15 \, C b^{4} \log \left (-\sin \left (d x + c\right ) + 1\right ) + 15 \, {\left ({\left (3 \, A + 4 \, C\right )} a^{3} b + 4 \, {\left (A + 2 \, C\right )} a b^{3}\right )} d x + {\left (6 \, A a^{4} \cos \left (d x + c\right )^{4} + 30 \, A a^{3} b \cos \left (d x + c\right )^{3} + 4 \, {\left (4 \, A + 5 \, C\right )} a^{4} + 60 \, {\left (2 \, A + 3 \, C\right )} a^{2} b^{2} + 30 \, A b^{4} + 2 \, {\left ({\left (4 \, A + 5 \, C\right )} a^{4} + 30 \, A a^{2} b^{2}\right )} \cos \left (d x + c\right )^{2} + 15 \, {\left ({\left (3 \, A + 4 \, C\right )} a^{3} b + 4 \, A a b^{3}\right )} \cos \left (d x + c\right )\right )} \sin \left (d x + c\right )}{30 \, d} \]
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Timed out. \[ \int \cos ^5(c+d x) (a+b \sec (c+d x))^4 \left (A+C \sec ^2(c+d x)\right ) \, dx=\text {Timed out} \]
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Time = 0.20 (sec) , antiderivative size = 239, normalized size of antiderivative = 0.96 \[ \int \cos ^5(c+d x) (a+b \sec (c+d x))^4 \left (A+C \sec ^2(c+d x)\right ) \, dx=\frac {8 \, {\left (3 \, \sin \left (d x + c\right )^{5} - 10 \, \sin \left (d x + c\right )^{3} + 15 \, \sin \left (d x + c\right )\right )} A a^{4} - 40 \, {\left (\sin \left (d x + c\right )^{3} - 3 \, \sin \left (d x + c\right )\right )} C a^{4} + 15 \, {\left (12 \, d x + 12 \, c + \sin \left (4 \, d x + 4 \, c\right ) + 8 \, \sin \left (2 \, d x + 2 \, c\right )\right )} A a^{3} b + 120 \, {\left (2 \, d x + 2 \, c + \sin \left (2 \, d x + 2 \, c\right )\right )} C a^{3} b - 240 \, {\left (\sin \left (d x + c\right )^{3} - 3 \, \sin \left (d x + c\right )\right )} A a^{2} b^{2} + 120 \, {\left (2 \, d x + 2 \, c + \sin \left (2 \, d x + 2 \, c\right )\right )} A a b^{3} + 480 \, {\left (d x + c\right )} C a b^{3} + 60 \, C b^{4} {\left (\log \left (\sin \left (d x + c\right ) + 1\right ) - \log \left (\sin \left (d x + c\right ) - 1\right )\right )} + 720 \, C a^{2} b^{2} \sin \left (d x + c\right ) + 120 \, A b^{4} \sin \left (d x + c\right )}{120 \, d} \]
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Leaf count of result is larger than twice the leaf count of optimal. 753 vs. \(2 (238) = 476\).
Time = 0.37 (sec) , antiderivative size = 753, normalized size of antiderivative = 3.01 \[ \int \cos ^5(c+d x) (a+b \sec (c+d x))^4 \left (A+C \sec ^2(c+d x)\right ) \, dx=\text {Too large to display} \]
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Time = 17.98 (sec) , antiderivative size = 2241, normalized size of antiderivative = 8.96 \[ \int \cos ^5(c+d x) (a+b \sec (c+d x))^4 \left (A+C \sec ^2(c+d x)\right ) \, dx=\text {Too large to display} \]
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